If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Finish the solution so that it returns the sum of all the multiples of 3 or 5 below the number passed in.
Additionally, if the number is negative, return 0.
Note: If a number is a multiple of both 3 and 5, only count it once.
Courtesy of projecteuler.net (Problem 1)
function solution(n) {
if (n < 0) return 0;
let s = 0;
for (let i = 0; i < n; i++) {
if (i % 5 === 0 && i % 3 === 0) {
s += i;
} else if (i % 5 === 0) {
s += i;
} else if (i % 3 === 0) {
s += i;
}
}
return s;
}
function solution(n) {
if (n < 0) return 0;
return Array.from({ length: n }).reduce((s, _, i) => {
if (i % 5 === 0 && i % 3 === 0) {
s += i;
} else if (i % 5 === 0) {
s += i;
} else if (i % 3 === 0) {
s += i;
}
return s;
}, 0);
}
function solution(n) {
if (n < 0) return 0;
return Array.from({ length: n }).reduce((s, _, i) => {
if (i % 5 === 0 || i % 3 === 0) {
s += i;
}
return s;
}, 0);
}
function solution(n) {
if (n < 0) return 0;
return Array.from({ length: n }).reduce(
(s, _, i) => (i % 5 === 0 || i % 3 === 0 ? (s += i) : s),
0
);
}